5X00082H12模块备件

5X00082H12

A6140低压降稳压器（LDO）在轻负载下仅消耗2μA的静态电流，并提供：
卓越的线路和负载瞬态性能。这些特性与低噪声和良好的PSRR相结合
具有低压降电压，使该设备成为便携式消费应用的理想选择。
热考虑
当结温过高时，热保护电路向控制逻辑发送信号
这将关闭集成电路。当温度充分冷却时，IC将重新启动。大值
功耗取决于外壳和电路板的热阻、温度
管芯接头和环境空气之间的差异以及空气流动速率。GND引脚必须为
连接到接地平面以进行适当的耗散。
申请须知：
1.电路内部使用相位补偿电路和输出电容器的ESR
补偿，因此大于1.0uF的电容器必须接地。
2.建议使用1uF极性电容器进行输入和输出，并保持电容器尽可能接近
尽可能连接到LDO的VIN和VOUT引脚。
3.注意输入、输出电压和负载电流的使用条件，避免电源
IC内部的功耗（PD）超过封装允许的大功耗。
PD=（VIN－VOUT）×IOUT
TPN=PD×RθJA+T
TPN是结温度
T是环境温度。
4.当输入电压VIN大于2.5V时，如果VIN也高于输出设定值加上
器件压降电压VOUT等于设定值。否则，VOUT等于VIN减去压降
电压如果VIN低于2.5V，则VOUT为：
VOUT=VIN-VDropout

5X00082H12

5X00082H12

The A6140 low-dropout regulators (LDO) consumes only 2μA of quiescent current at light load and delivers excellent line and load transient performance. These characteristics, combined with low noise and good PSRR with low dropout voltage, make this device ideal for portable consumer applications. Thermal Considerations When the junction temperature is too high, the thermal protection circuitry sends a signal to the control logic that will shut down the IC. The IC will restart when the temperature has sufficiently cooled down. The maximum power dissipation is dependent on the thermal resistance of the case and the circuit board, the temperature difference between the die junction and the ambient air, and the rate of air flow. The GND pin must be connected to the ground plane for proper dissipation. Applications Note: 1. The phase compensation circuit and ESR of the output capacitor are used inside the circuit to compensate, so a capacitor larger than 1.0uF must be connected to the ground. 2. It is recommended to use 1uF polar capacitors for input and output, and to keep the capacitors as close to the VIN and VOUT pins of LDO as possible. 3. Pay attention to the use conditions of input and output voltages and load currents to avoid the power consumption (PD) inside the IC exceeding the maximum power consumption allowed by the package. PD=(VIN－VOUT)×IOUT TPN = PD×RθJA+T TPN is junction temperature T is ambient temperature. 4. When the input voltage VIN is greater than 2.5V, if VIN is also higher than the output set value plus the device dropout voltage, VOUT is equal to the set value. Otherwise, VOUT is equal to VIN minus the dropout voltage. If VIN lower than 2.5V, the VOUT is: VOUT = VIN - VDropout